Grade and antigrade: Difference between revisions
Jump to navigation
Jump to search
Eric Lengyel (talk | contribs) No edit summary |
Eric Lengyel (talk | contribs) No edit summary |
||
Line 8: | Line 8: | ||
[[Scalars]] have grade 0, and [[antiscalars]] have grade ''n''. [[Vectors]] have grade 1, and [[antivectors]] have antigrade 1. [[Bivectors]] have grade 2, and [[trivectors]] have grade 3. | [[Scalars]] have grade 0, and [[antiscalars]] have grade ''n''. [[Vectors]] have grade 1, and [[antivectors]] have antigrade 1. [[Bivectors]] have grade 2, and [[trivectors]] have grade 3. | ||
== In the Book == | |||
* Grade and antigrade are introduced in Section 2.1.4. | |||
== See Also == | == See Also == | ||
Line 13: | Line 17: | ||
* [[Duality]] | * [[Duality]] | ||
* [[Complements]] | * [[Complements]] | ||
Latest revision as of 23:31, 13 April 2024
The grade of a basis element in a geometric algebra is equal to the number of basis vectors present in its factorization. An arbitrary element whose components all have the same grade is also said to have that grade.
The antigrade of a basis element is equal to the number of basis vectors absent from its factorization.
The grade of an element $$\mathbf x$$ is denoted by $$\operatorname{gr}(\mathbf x)$$, and the antigrade is denoted by $$\operatorname{ag}(\mathbf x)$$. In an n-dimensional geometric algebra, it is always the case that
- $$\operatorname{gr}(\mathbf x) + \operatorname{ag}(\mathbf x) = n$$ .
Scalars have grade 0, and antiscalars have grade n. Vectors have grade 1, and antivectors have antigrade 1. Bivectors have grade 2, and trivectors have grade 3.
In the Book
- Grade and antigrade are introduced in Section 2.1.4.